解题思路
加个头，加个尾，然后正常从index = 1开始找问号，找到就看下前后是不是有相同的
正常替换
最后掐头去尾return
代码
class Solution
{
public:
string modifyString(string s)
{
string temp = "?" + s + "?";
string result = "";
for (size_t loop = 1; loop < temp.length() - 1; loop++)
{
if (temp.at(loop) == '?')
{
for (char looptimes = 'a'; looptimes <= 'z'; looptimes++)
{
if (temp.at(loop - 1) != looptimes && temp.at(loop + 1) != looptimes)
{
temp.at(loop) = looptimes;
}
}
}
}
for (size_t loop = 1; loop < temp.length() - 1; loop++)
{
result += temp.at(loop);
}
return result;
}
};
Silverhand Miles 